x >> nReturns $x / p^n = x \cdot p^{-n}$, shifting the $p$-adic expansion right by $n$ places. A negative shift multiplies by $p^{|n|}$.
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The source of this document is in /build/reproducible-path/macaulay2-1.26.05+ds/M2/Macaulay2/packages/Padic.m2:793:0.